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Trigonometry 20 Online
OpenStudy (anonymous):

find the exact value of cos^-1 (0) without a calculator. I do not understand how to.

OpenStudy (anonymous):

it is the same as this one: cos(x)=0 x=?

OpenStudy (anonymous):

@chloe.pearson ,can u find x?

OpenStudy (anonymous):

would it just be 1? I am confused as to how cos^-1 (0) is = to cosx=0

OpenStudy (anonymous):

so in a similar question, sin^-1 (1), it would be sinx=1? but I dont know where sinx=1

OpenStudy (anonymous):

: To find cos-1 (0), it asks "what angle has cosine equal to 0

OpenStudy (anonymous):

at 0 and pi?

OpenStudy (anonymous):

cos or sin?

OpenStudy (anonymous):

for cos?

OpenStudy (anonymous):

no,can u draw a figure?

OpenStudy (anonymous):

@chloe.pearson ,?

OpenStudy (anonymous):

for cos^-1 0, would it be pi/2 +/- Npi?

OpenStudy (anonymous):

pi/2 is right

OpenStudy (anonymous):

and can u say the next one?

OpenStudy (anonymous):

for sin?

OpenStudy (anonymous):

no again for cos

OpenStudy (anonymous):

or for cos, I think the next one would be 3pi/2

OpenStudy (anonymous):

good

OpenStudy (anonymous):

would sin^-1 (1) be pi/2?

OpenStudy (anonymous):

yeah,u r right

OpenStudy (anonymous):

awesome thankyou!

OpenStudy (anonymous):

ur welcome

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