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find the exact value of cos^-1 (0) without a calculator. I do not understand how to.
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it is the same as this one: cos(x)=0 x=?
@chloe.pearson ,can u find x?
would it just be 1? I am confused as to how cos^-1 (0) is = to cosx=0
so in a similar question, sin^-1 (1), it would be sinx=1? but I dont know where sinx=1
: To find cos-1 (0), it asks "what angle has cosine equal to 0
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at 0 and pi?
cos or sin?
for cos?
no,can u draw a figure?
@chloe.pearson ,?
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for cos^-1 0, would it be pi/2 +/- Npi?
pi/2 is right
and can u say the next one?
for sin?
no again for cos
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or for cos, I think the next one would be 3pi/2
good
would sin^-1 (1) be pi/2?
yeah,u r right
awesome thankyou!
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ur welcome
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