Question

(sin x )sin x cos^2x = sin^3x

Answer 1

prove identities

Answer 2

are you sure it's an identity?
\[\sin^{2}(x) *\cos(x)=\sin ^{3}(x)\]

Answer 3

\[\sin x - \sin x \cos ^2x=\sin ^3x\]

Answer 4

sorry for the confusion.

Answer 5

okay, now we are talking :)
\[=\sin(x) [1-\cos ^{2}(x)] \rightarrow \sin(x)*\sin ^{2}(x)= \sin ^{3}(x)\]

Answer 6

ah! I see, because sin^2x+cos^2x=1

so sin^2x=1-cos^2x

Answer 7

that's so right @Mathdude101 ;)