Question

A ball is dropped from 15.6m. Another ball is thrown upwards. The motions are reverse of each other. How to find the location they cross paths?

Answer 1

let the height h=15.6m
let the height of cross point frm ground is =x
so the falling ball will travell 15.6-x
now we will use the equation h=ut+(1/2)gt^2
this equation is for free fall ball will b
15.6-x=ut+(1/2)gt^2
15.6-x=0*t+(1/2)gt^2.............(1)
for upward going ball this equation will b
x=ut-(1/2)gt^2.................(2)
now u will add equation 1 and rquation 2

Answer 2

need some more informaton