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Mathematics 8 Online
OpenStudy (anonymous):

Solve –2x^2 +3x – 9 = 0

OpenStudy (uri):

Again Quad formula!

OpenStudy (anonymous):

So quadratic equation again:)

OpenStudy (uri):

a:-2 b:3 c:-9

OpenStudy (anonymous):

i tried but i dont get an answer choice that i can choose

OpenStudy (anonymous):

You can factor this one...

OpenStudy (anonymous):

just post your steps and results here and we'll help

OpenStudy (anonymous):

is the answer \[x=\frac{-3 \pm 3i \sqrt{7}}{-4}\]

OpenStudy (anonymous):

i got that :) ..ts correct

OpenStudy (anonymous):

but i cant choose that answer. all my answer choices are over positive 4

OpenStudy (anonymous):

Wait....But if you solve it by factoring you get something else...?

OpenStudy (anonymous):

and whats that

OpenStudy (anonymous):

-3 and 3/2.

OpenStudy (anonymous):

check this out, i just want you to see whats right. not saying that this is though http://au.answers.yahoo.com/question/index?qid=20100313194503AASfWpU

OpenStudy (anonymous):

thats not it.... -3+3/2 not equals 3

OpenStudy (anonymous):

well that would make sense if i could use and answer choice as simple as that.

OpenStudy (anonymous):

well @OpenSessame , that has +2x^2 and this has -2x^2

OpenStudy (anonymous):

AHHH

OpenStudy (anonymous):

ah i see what you did there

OpenStudy (anonymous):

@jj911832 ..you sure the question is right mate?

OpenStudy (anonymous):

yes that is defiantly the question.. unless my teacher put it in wrong..

OpenStudy (anonymous):

definitely*

OpenStudy (anonymous):

DId you anwer match one of your choices?

OpenStudy (anonymous):

i just submitted it and i was rite when i put in my first answer\[x= \frac{3\pm3i \sqrt{7}}{4}\]

OpenStudy (anonymous):

yay :)

OpenStudy (anonymous):

Good:)

OpenStudy (anonymous):

but i got this one wrong Solve –2x2 – 16x – 44 = 0

OpenStudy (anonymous):

first divide by -2

OpenStudy (anonymous):

that makes sense seeming i divided by positive 2

OpenStudy (anonymous):

its a messy answer :). what did you get?

OpenStudy (anonymous):

@jj911832 you there mate?

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