Question

show that integral from 0 to t f(u)du is 1/s L(s) (laplace transform

Answer 1

Do mean to show that \[\int_0^\infty e^{-st}dt=\frac1s\]?

Answer 2

@freddy_eighty7 Is that 1/s being mulyipling by L(s)?

Answer 3

[\int\limits_{0}^{t} f(u) du = 1/s L sub f (s) \]
if that makes sense

Answer 4

\[\int_0^t f(u) du =\frac1s L ( f (u)) \]?

Answer 5

yes