Question

which of the following are the solutions to the equation below? Check all that apply.
(2x-3)^2=1
a.-1
b.3
c.-2
d.1/3
e.2
f.1

Answer 1

Substitute all the values into x and see if you get 1, if you did, then that value of x is a solution to the equation

Answer 2

B. and D. are out of the list

Answer 3

Still got more out of list

Answer 4

No

Answer 5

Since there are multiple solutions, you are better off finding the solutions, instead of testing all 5 choices.
\( (2x-3)^2 =1 \\
=> \\
(2x-3)=\pm 1
\)
So solve for
\( 2x-3=1\\
and\\
(2x-3)=-2
\)
to find your answer.

Answer 6

Sorry, last one should read:
\( (2x-3)=-1\)

Answer 7

No

Answer 8

c nd e??

Answer 9

Did you solve for x in the two equations I posted earlier?
What did you get?

Answer 10

2,-2

Answer 11

Can you check your second answer?

Answer 12

wait it -1 got confussed

Answer 13

its a nd e

Answer 14

Sure it's -1?

Answer 15

Are you sure the second answer is -1?

Answer 16

Solve
\((2x−3)=−1\)

Answer 17

for the second equation there both - so its +1

Answer 18

So what are the solutions of the equations?

Answer 19

i mean -2

Answer 20

ohhhhh d nd e

Answer 21

No

Answer 22

For the second equation:
\((2x−3)=−1\\
2x=-1+3=2\\
x=1\)
Do you agree?

Answer 23

isnt it -1

Answer 24

Show me how you got -1, please.

Answer 25

-+=- right

Answer 26

@romanortiz65 you still there?

Answer 27

yeah

Answer 28

So can you show me how did you get x=-1 from
\((2x−3)=−1\)
This will help you avoid future errors.

Answer 29

2x-3=-1
+3 +3
2x=-2
x=-1

Answer 30

-1 + 3 = 3 - 1 = 2

Answer 31

On the right hand side, -1+3 equals -2.
I will show this on the number line:

Answer 32

Sorry again,
-1+3=+2

Answer 33

So what are the two solutions that we have found?

Answer 34

-1, 2

Answer 35

A,E

Answer 36

No

Answer 37

what the heck im confffused

Answer 38

e nd f

Answer 39

its okay... slow down

Answer 40

There you go!

Answer 41

\[2x = 4\]and \[2x - 3= -1\]Thats how you get E and F