Question

where does the function intersect the x-axis ?

f(x)=(x-1)(x+2)(x-3)

Answer 1

we want f(x) = 0
so
(x-1)(x+2)(x-3) = 0
this happens when
(x-1) = 0
(x+2)=0
(x-3) = 0

Answer 2

think about a*b=2
there are infinite things we can make a,b to make this true
a = 1/2, b = 4
a = 1/8, b = 16
a = 32, b = 1/16
......

but when we have
ab=0 there are only three things that can happen
a=0, b=0, or a and b are both 0

Answer 3

so for (x-1) i would set x=+1
& for (x+2) i would set x=-2
then for (x-3) i would set x=+3
right ??

Answer 4

correct

Answer 5

so f(x)=0*0*0
f(x)=0
so the function intersects with the x-axis 0 times ?