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Mathematics 21 Online
OpenStudy (anonymous):

solve>>>> see below

OpenStudy (anonymous):

\[x ^{2}-12=4x\]

OpenStudy (anonymous):

\[x ^{2}-4x-12=0 ???\]

OpenStudy (anonymous):

in school do they teach you quadratic formula or factor method?

OpenStudy (anonymous):

x^2+2x-6x-12 Factor !!

OpenStudy (anonymous):

quadratic formula

OpenStudy (anonymous):

supraron you lost me

OpenStudy (chaise):

Start by making the equation equal to 0, do this by -4x both sides of the equation. x^2-4x-12=0 Now in order to factorise you are looking for two numbers which add to give -4 and multiply to give -12. In this cause the two factors are x=2 x=-6 Thus: (x+2)(x-6)=0 For this equation to be true x=-2 x=6

OpenStudy (anonymous):

do you know what is the quadratic formula?

OpenStudy (anonymous):

Oh then plug in the numbers \[-b \pm \sqrt{b^2-4ac} all \over 2a\]

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