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Mathematics 21 Online
OpenStudy (anonymous):

Point P is the center of two concentric circles. PQ = 2.5 and PS = 5. RS is tangent to the smaller circle and a chord of the larger circle. What is length of RS to the nearest tenth?

OpenStudy (anonymous):

OpenStudy (anonymous):

please help @ybarrap

OpenStudy (anonymous):

@katherine.ok

OpenStudy (anonymous):

angle PQS = 90degrees.

OpenStudy (anonymous):

yes but im trying to find the length of RS

OpenStudy (anonymous):

you know that PQ=2.5 , PS=5

OpenStudy (anonymous):

Looking at a triangle PQS (a right triangle indeed) you can get QS

OpenStudy (anonymous):

hmm i dont understand

OpenStudy (anonymous):

and because the smaller circle and the larger circle share the same centre, assumeQS=RQ

OpenStudy (anonymous):

(PS)^2= (PQ)^2+(QS)^2, get QS from this pythagorean theorem.

OpenStudy (anonymous):

once you get QS, you know that RQ is of same length therefore total length of that RS is 2* QS.

OpenStudy (ybarrap):

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