A triangle has an area of 10cm^2. The height of the triangle is 4cm longer than three times the base. (((((((Find the height and base of the triangle)))))))
Area of a triangle= 1/2 base x height 10= 1/2 (b)(3b+4)
solve that out for b to get your base and then the height is 3b+4
.5base x height???
do I want to move everything over to the left except the base?
isolate the b on one side, so yes
10= 1/2 (b)(3b+4) 10= 1/2 (3b^2+4b) 20= 3b^2+4b 3b^2+4b-20= 0
(3b+10)(b-2)= 0 3b=-10 or b=2 b=-10/3
However, if you think about it logically, can a base ever be negative?
No it can not
Thus, the base is 2 and the height is 3(2)+4= 6+4=10
understand?
the height is 10??
yes, because the height= 3b+4 and the base is 2 so 3(2)+4 6+4 10
0r\[-\frac{ 10 }{ 3 }\]
A base or height can never be negative though
ok I got it.
okay cool :)
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