Question

determine the intercepts: 2x-3y=6

Answer 1

do i start by using y = mx+b?

Answer 2

for x-intercept put y=0
and for y-intercept put x=0 and solve the resulting equaions respectively

Answer 3

?
so i graph the line?

Answer 4

otherwise reduce the given equation to the form
(x/a) +(y/b)=1 where a and b are the x and y intercepts respectively

Answer 5

i dont get it

Answer 6

2x-3y=6
(2x-3y)=1
2x/6 -3y/6 =1
or
x/3 +y/(-2) =1

Answer 7

ya i got that but from here, how do i graph x/3 +y/2?

Answer 8

instead of x/3 +y/2
it is x/3 +y/(-2) =1
the line passes through (3,0) and (0,-2)

Answer 9

but if x/3=0 then it would be x=0*3 and x =0?

Answer 10

for (x/a) +(y/b)=1 the line passes through (a,0) and (0,b)

Answer 11

Method 1
for x-intercept we put y=0 in 2x-3y=6
hence we have
2x-3(0)=6
or 2x=6 or x=3

Answer 12

similarly for y-intercept we put x=0 in 2x-3y=6
we get
2(0)-3y=6
or
-3y=6
or y=-2

Answer 13

double checking hold on

Answer 14

mmkay i got it from here

Answer 15

keep it up

Answer 16

so i got 3,0 and 0,-2

Answer 17

this the final answer?