Question

Solve the systems using substitution.

6x + 2y = 0
4x + y = -1

3x + 2y = -4
x + 2y = -8

5x - 4y = 14
x - 2y = -2

x + 3y = -4
4x + 5y = 5

x + 3y = -5
2x - y = 18

Answer 1

Just TAKE X VALUES OF ALL IN TERMS OF Y AND THEN JUST SUBSTITUTE IN THE 2ND EQUATIONS!! :) [TRY]

Answer 2

these a lot which one you want to solve

Answer 3

The first one and then i think i could do the rest

Answer 4

ok

Answer 5

6x+2y=0
-6x= -6x
2y=-6x

Answer 6

any reply

Answer 7

i dont understand

Answer 8

it like you have to leave y by it self

Answer 9

so the answer is y=-3y

Answer 10

6x + 2y = 0
subtract 6x on both sides and its 2y=-6x
divide each side by 2 so y=-3x plug it in to
4x + y = -1 so 4x + -3x = -1
X=-1 now solve for Y by plugging X in 4(-1) +y=-1
-4+y=-1
Add 4 to both sides
y=3

Answer 11

To test it plug the numbers into 6x + 2y = 0
6(-1) + 2(3) = 0
-6+6=0

Answer 12

Do you understand how to do the rest? and can I get a medal please :)

Answer 13

yes