Question

Lyle has a bowl of fruit on his dining room table. It contains 2 oranges, 6 apples, and 2 peaches. Suppose he selects a piece of fruit at random from the bowl. What is the probability that he selects either an apple or a peach?

twenty percent

forty percent

sixty percent

eighty percent

Answer 1

\[P(\text{a or p}) = \frac{\text{apple + peach}}{\text{total fruit}}\]

Answer 2

@chrisrodr02 are you there?

Answer 3

ohh yeah my bad i was soing the rest of my hw

Answer 4

Can you find the fraction for P(a or p)?

Answer 5

i really dont know how to do it?

Answer 6

You find the probability of choosing an apple, then the probability of choosing a peach. Then you add them together. I posted a formula above to help you.

Answer 7

ok thank you!

Answer 8

Just to make sure, you should post the fraction you get for P(a or p)

Answer 9

is it 6/2??

Answer 10

How did you get that?

Answer 11

Let's do it this way...

Answer 12

Fill out this:

Total apples in bowl =
Total peaches in bowl =
Total fruit in bowl =

Answer 13

is it 8/10

Answer 14

Yes, but reduce it

Answer 15

4/5

Answer 16

Okay, so percentage wise, what does 4/5 represent?

Answer 17

80 %

Answer 18

Great job

Answer 19

thank you