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OpenStudy (anonymous):
which of the following are solutions to the equation
Check all that apply.
x^2-6x+9=11
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OpenStudy (anonymous):
a.\[x=\sqrt{11}+3\]
OpenStudy (anonymous):
B.\[x=-\sqrt{2}+6\]
OpenStudy (anonymous):
C.\[x=2-\sqrt{6}\]
OpenStudy (anonymous):
D.\[x=-\sqrt{11}-3\]
OpenStudy (anonymous):
\[\left( x-3 \right)^{2}=11\]
\[x-3=\pm \sqrt{11}\]
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OpenStudy (anonymous):
F.\[\sqrt{2}+6\]
OpenStudy (anonymous):
your answer?
OpenStudy (anonymous):
E.\[x=2+\sqrt{6}\]
OpenStudy (anonymous):
dont get it
OpenStudy (anonymous):
\[x^2-6x+9=11 \]\[(x-3)^2 = 11\]Now take the square root and...
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OpenStudy (anonymous):
Huh?
OpenStudy (anonymous):
its A and D
OpenStudy (anonymous):
\[x-3 = \pm \sqrt{11}\]\[x = \pm \sqrt{11}+3\]What are they?
OpenStudy (anonymous):
Cannot be D... Unless D is +3 and not -3
OpenStudy (anonymous):
Did you have a typo?
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OpenStudy (anonymous):
the 3 is +3
OpenStudy (anonymous):
okay! Then yes! A and D
OpenStudy (anonymous):
\[x=\sqrt{11}+3 andx=-\sqrt{11}+3\]
OpenStudy (anonymous):
thanks man hey omw to work thanks alot ima have to finish my test tomorrow
OpenStudy (anonymous):
seriously. thats exactly what i said
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OpenStudy (anonymous):
lol ur going to work to
OpenStudy (anonymous):
no. "thats exactly what I said" means I told you the same thing surji said but faster/first
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