Find the exact value of the real number y.

y = csc^-1(1)

Question

Find the exact value of the real number y.

y = csc^-1(1)

anonymous · Answer

i believe it is pi/4

anonymous · Answer

csc is the inverse of sine.

e.mccormick · Answer

Not quite...

anonymous · Answer

so its basically asking you to find get angle when sin is (1)^-1.

e.mccormick · Answer

(not quite $\frac{\pi}{4}$ that is...)

anonymous · Answer

ok, i tried it again, and i got pi/2 this time, i know it isnt 2pi because that would be a full circle, and it isnt pi because that would be half a circle

e.mccormick · Answer

Yah, $\frac{\pi}{2}$.  The top of the unit circle.

e.mccormick · Answer

Have you seen the graphs of the periodic functions?  It might help you understand the concept a little better.

e.mccormick · Answer

If you look at this graph: https://www.desmos.com/calculator/xr6ycnqkfr You can turn off the parts you do not need. Leave on the line $x=\tfrac{\pi}{2}$ and $\csc x$. You can see that at that value of x, the y value is 1. Well, $\csc^{-1}$ or arccsc is the inverse function, so that question meant "When Y is 1, what is the X value for csc?" Hope that helps you see it another way.