how would i solve this to tell if it is always, sometimes, or never true? 2/3x+4=2x
\[\frac{2}{3x}+4=2x\] multiply both sides by 3x so equation becomes \[2+4(3x)=2x(3x)\]now solve for x
it's sometimes. because if you put 3 into the equation, it works. but if you put 0 it doesn't.
thank you so much! how would you solve these equations 1. (m-2)-5=8-2(m-4) and A=1/2h(b1+b2) solving for b2
Use the idea of balance
Whatever you do to one side you do to the other.
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so for quesiton 1. you move the numbers to one side. so it turns into (m-2)+2(m-4)=8+5 when you move the numbers to one side the signs in front of the numbers needs to be changed also. then it'll turn into 3m-10=13 3m=23
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