solve the simultaneous equation using the substitution method:

x/2+y/4=5
4x/3+5y/8=13

Question

solve the simultaneous equation using the substitution method: 

x/2+y/4=5
4x/3+5y/8=13

anonymous · Answer

Q8 of the image

texaschic101 · Answer

multiply the first equation by 4 and the second equation by 24 and get rid of the fractions

jack1 · Answer

x/2 + y/4 = 5    EQN 1
multiply equation 1 by 4
= 2x +y = 20 = EQN 1a
re arrange EQN 1a
y = 20 - 2x

4x/3 + 5y/8 = 13  EQN 2
sub y = 20 - 2x into EQN 2
4x/3 + 5(y)/8 = 13 
4x/3 + 5(20 - 2x)/8 = 13

solve for x

jack1 · Answer

use that x value to solve for y

jack1 · Answer

@harry.g1234 ... how're u going following the above dude...? u ok, want something explained a little clearer...?

anonymous · Answer

Thanks alot i really appreciate your help 
its very clear now thanks

anonymous · Answer

@Jack1

jack1 · Answer

sweet as 'slaters

anonymous · Answer

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