Find the common difference for the sequence shown. 56, 49, 42, 35, ... -12 -7 7
-7
What is the method for finding common difference?
The difference is 7. You cant have a difference of a negative number.
56 - 49 = ? 49 - 42 = ? 42 - 35 = ? The difference is found when you subtract the first number from the one coming after it.
yes the difference is 7 but you have to use a negative to subtract otherwise you would be adding.
Common difference is not first number - second number. It is second number - first number. It can be positive or negative, which denotes whether the sequence is increasing or decreasing. The common difference is 49 - 56 = -7
Ahh, my bad.
$$\tt a_1+(n-1)d=a_n\text{ for n=1,2,... and d>0. }\\\text{Here d = 7}. $$
@ybarrap If you put 7 for d in your equation you will get a sequence different from the one in the question. d can be negative as well.
You are right! d = -7, sorry about that. $$a_1=56\\ a_2=56+(2-1)*(-7)=56-7=49\\ a_3=56+(3-1)*(-7)=56-14=42\\ etc. $$
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