Trevor is tiling his bathroom floor, which has an area that is represented as 120r3 square inches. Each tile has an area of square root of the quantity 16 r to the ninth power. The total number of tiles used can be represented by the expression below.
one hundred twenty r to the third power, all over the square root of the quantity sixteen r to the ninth power

Question

Trevor is tiling his bathroom floor, which has an area that is represented as 120r3 square inches. Each tile has an area of square root of the quantity 16 r to the ninth power. The total number of tiles used can be represented by the expression below.
one hundred twenty r to the third power, all over the square root of the quantity sixteen r to the ninth power

anonymous · Answer

@ankit042 i need more help pleasee

anonymous · Answer

attachment

ankit042 · Answer

try solving the denominator first

anonymous · Answer

sqrt(8r^3)?

ankit042 · Answer

NO it will be 4r^3*sqrt(r^3)

anonymous · Answer

how?

anonymous · Answer

is that a 9/3?

anonymous · Answer

@ybarrap why did you delete that :( i wanted you to explain it to me

ankit042 · Answer

I think it will be 4r^3*sqrt(r^3) like the last time we did
16r^9 can be written as 4r^3*4r^3*r^3
after putting sqrt we will get 4r^3*sqrt(r^3)

ybarrap · Answer

$$
	t
\large\frac{120r^3}{\sqrt{16r^9}}
\large=\frac{120r^3}{\sqrt{16}r^{9/2}}
\large=\frac{120r^{3-9/2}}{4}\
\large=\frac{120r^{-3/2}}{4}
\large=\frac{120}{4r^{3/2}}\
\large=\frac{30}{r^{3/2}}\
$$

ybarrap · Answer

let me know if you have any questions

anonymous · Answer

im just looking over it and seeing what you did step by step (: