Use an algebraic equation to solve

A rectangle is 3 times as long as it is wide the perimeter is 60cm find the dimensions of the rectangle round to nearest tenth if you have to

Question

Use an algebraic equation to solve

A rectangle is 3 times as long as it is wide the perimeter is 60cm find the dimensions of the rectangle round to nearest tenth if you have to

kropot72 · Answer

Let the width of the rectangle be x cm. Then the length will be 3x cm.
The perimeter is
$$60=2\times x+2\times 3x\ .....(1)$$
Can you solve equation (1) to find x?

anonymous · Answer

I'm usually pretty good in math but this one has just confused me @kropot72

kropot72 · Answer

The perimeter is twice the width plus twice the length, as shown in equation (1). Simplifying equation (1) we get
60 = 2x + 6x ............(2)
If you add the two terms on the right hand side of equation (2) you will get a simple equation to solve for x.

anonymous · Answer

Ok so that will come out to be 60 = 8x

kropot72 · Answer

Correct. Now divide both sides of '60 = 8x' by 8 to find the value of x.

anonymous · Answer

7.5cm by 22.5cm?

anonymous · Answer

@kropot72

kropot72 · Answer

Good work! Your answer is correct.