Question

kinematics in 2d, you are given a particle which moves horizontally. you are just given the horizontal and vertical components of the velocity, how would u go about finding the positions of the particle at the given instants of time?

Answer 1

Somebody please help me out

Answer 2

You wouldn't be able to find a position at a time without knowing the position at another time!

\(x_t=x_{t=0}+v\ t\)
You can find the displacement, though. You would let \(x_{t=0}=0\), and then \(x_t=0+v\ t=v\ t\). Technically, the \(x\) component of displacement is \(\large \overrightarrow{x_{t_2}}-\overrightarrow{x_{t_1}}\).

Answer 3

I assumed you knew some formulas or how to get them. Feel free to ask any questions! :)

Answer 4

I was pretty wrong to say "\(\large \overrightarrow{x_{t_2}}-\overrightarrow{x_{t_1}}
\)."

I was going for \(\large \overrightarrow{r_{t_2}}-\overrightarrow{r_{t_1}}.
\)
Or it is fine to say just \(\large x_{t_2}-x_{t_1}\).