kinematics in 2d, you are given a particle which moves horizontally. you are just given the horizontal and vertical components of the velocity, how would u go about finding the positions of the particle at the given instants of time?

Question

anonymous · Answer

Somebody please help me out

theeric · Answer

You wouldn't be able to find a position at a time without knowing the position at another time!

$x_t=x_{t=0}+v\ t$
You can find the displacement, though. You would let $x_{t=0}=0$, and then $x_t=0+v\ t=v\ t$. Technically, the $x$ component of displacement is $\large \overrightarrow{x_{t_2}}-\overrightarrow{x_{t_1}}$.

theeric · Answer

I assumed you knew some formulas or how to get them. Feel free to ask any questions! :)

theeric · Answer

I was pretty wrong to say "$\large \overrightarrow{x_{t_2}}-\overrightarrow{x_{t_1}}
$."

I was going for $\large \overrightarrow{r_{t_2}}-\overrightarrow{r_{t_1}}.
$
Or it is fine to say just $\large x_{t_2}-x_{t_1}$.