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Find tan θ if sec θ = square root 37 / 6 and sin θ < 0.
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Well, if secant is positivwe but sin is negative, there is only one quadrant we can be in. Secant is 1/cos, and cos refers to x-values while sin refers to y-values. Once we know what quadrant we're in, we need to draw a triangle and label the appropriate sides of that triangle with sqrt37 and 6.Remember that secant is cosine flipped, so you would be placing sqrt 37/6 on hypotenuse/adjacent. Then just find the missing side via pythagorean theorem and take the appropriate values that will give you tan.
kinda make sense?
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