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Geometry 17 Online
OpenStudy (anonymous):

Given the triangle and equations below, what is the value of x?

OpenStudy (anonymous):

OpenStudy (jdoe0001):

so you have 2 sides there, what would be the missing side in the triangle using pythagorean theorem?

OpenStudy (anonymous):

13?

OpenStudy (anonymous):

Can i just have the answer pleaseeee? I just really need to move on from this question

OpenStudy (jdoe0001):

well \(\bf c^2 = a^2 + b^2 \implies b = \sqrt{c^2 -a^2} \implies b = \sqrt{13}\) |dw:1376606786732:dw| then recall that \(\bf sec(\theta) = \cfrac{hypotenuse}{adjacent} \implies \cfrac{c}{a}\\ cot(\theta) = \cfrac{adjacent}{opposite} \implies \cfrac{a}{b}\)

OpenStudy (anonymous):

Thank you :)

OpenStudy (jdoe0001):

yw

OpenStudy (anonymous):

But wait, whats the answer?

OpenStudy (jdoe0001):

you subtract those 2 values given for each function, equate it to 3x and solve for "x"

OpenStudy (anonymous):

A!

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