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Geometry
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Given the triangle and equations below, what is the value of x?
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so you have 2 sides there, what would be the missing side in the triangle using pythagorean theorem?
13?
Can i just have the answer pleaseeee? I just really need to move on from this question
well \(\bf c^2 = a^2 + b^2 \implies b = \sqrt{c^2 -a^2} \implies b = \sqrt{13}\) |dw:1376606786732:dw| then recall that \(\bf sec(\theta) = \cfrac{hypotenuse}{adjacent} \implies \cfrac{c}{a}\\ cot(\theta) = \cfrac{adjacent}{opposite} \implies \cfrac{a}{b}\)
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Thank you :)
yw
But wait, whats the answer?
you subtract those 2 values given for each function, equate it to 3x and solve for "x"
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