Question

(y/1+4x) (8 - x/y) (1+4x/y-x)

Perform Indicated Operations

Answer 1

What are the operations?

Answer 2

Well my book says multiply them all
Numerator and denominator. Then cancel out like terms
I'm stumped.

Answer 3

Well just multiply everything, but don't distribute them

Answer 4

Yes I know but I need to find LCD and I don't know what that is for the denominator

Answer 5

When you multiply you don't really need one, it's like when you're dealing with fractions:
\[\frac{1}{2}*\frac{5}{3}=\frac{5}{6}\]
It'd be like this right?

Answer 6

Yes. But then I need to cancel out like terms and sometimes that is where i find it confusing because I will cancel out 4xy with a y because i see a y. But these two terms are not the same

Answer 7

Here I'll get you started:
\[\frac{y}{1+4x}*\frac{8-x}{y}*\frac{1+4x}{y-x}=\frac{(y)(8-x)(1+4x)}{(1+4x)(y)(y-x)}\]
Now start canceling :)

Answer 8

do all three y's get canceled out?

Answer 9

my answer is 8x^2?

Answer 10

8-x^2 i mean

Answer 11

y and (1+4x) cancel, how did you get an x^2?

Answer 12

or perhaps the answer is just 8 lol

Answer 13

8 - x/y is in one parethesis

Answer 14

i canceled out both x's and i am left with 8