Henry grabs one shoe at a time at random without replacement from a box of ten shoes in his closet. The box contains 2 brown shoes, 4 black shoes, and 4 sneakers. What is the probability that the first two shoes he chooses will be brown? Round to the nearest percent if necessary.
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OpenStudy (anonymous):
1/50
OpenStudy (anonymous):
Is it 20%?
The answers are A)2%
B)20%
C)22%
D)40%
OpenStudy (anonymous):
2%
OpenStudy (anonymous):
I don't understand can you please explain how you got to that answer?
OpenStudy (anonymous):
First take, 2/10 = 1/5 = .2
Second take, 1/10 = .1
.2 * .1 = .02
.02 = 2%
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
without replacement!!!!
the denominator changes!!!!
OpenStudy (anonymous):
(2/10)*(1/9)
OpenStudy (anonymous):
not .02
OpenStudy (anonymous):
... my answer is still correct, round XD
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OpenStudy (anonymous):
.022222222222
OpenStudy (anonymous):
yeah but you r method is dead wrong... so how could he do it again?