Question

Simple Integral Problem:

Answer 1

\[\int\limits \frac{\sin2x}{cosx} dx\]

Answer 2

Use an identity. sin2x = 2sinxcosx

Answer 3

So change it to:
\[\int\limits \frac{2sinxcosx}{cosx}\]

Answer 4

*dx

Answer 5

simple?! what the heck is this? doesn't look liek any algebra i seen before

Answer 6

@abb0t quit playing, you know this.

Answer 7

It's sin is what it is. PURE SIN!

Answer 8

But yes @Luigi0210 , then cosx cancels and you can integrate just fine from there.

Answer 9

\[2 \int\limits sinx dx=-2cosx +C\]

Answer 10

Thank you @Psymon "_

Answer 11

*:)

Answer 12

I have no idea what's going on, literally.