okay first i need to know what the formula is and how it works.(warning im tried so i may act silly or it may take me time to understand it:P)
Solve the following using the quadratic formula. Round to the nearest tenth, if necessary.
x2 + 5x - 2 = 0

{-2, 5}
{-5.4, 0.4}
{-1, 0.5}
No real solution

Question

okay first i need to know what the formula is and how it works.(warning im tried so i may act silly or it may take me time to understand it:P) 
Solve the following using the quadratic formula. Round to the nearest tenth, if necessary.
x2 + 5x - 2 = 0

    {-2, 5} 
   {-5.4, 0.4} 
   {-1, 0.5} 
   No real solution

anonymous · Answer

@timo86m

jim_thompson5910 · Answer

do you know the quadratic formula?

anonymous · Answer

no sir

jim_thompson5910 · Answer

the quadratic formula is

$$\large x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$$

jim_thompson5910 · Answer

in this case, a = 1, b = 5 and c = -2

plug those 3 values in and simplify

anonymous · Answer

$$x=-5+\sqrt{5^2-4*1*(-2)}/ 2*1$$

jim_thompson5910 · Answer

close, don't forget about the plus/minus

$$\Large x = \frac{-5\pm\sqrt{5^2-4(1)(-2)}}{2(1)}$$

jim_thompson5910 · Answer

keep going and simplify

anonymous · Answer

would i go by the PEMDAS to simplfy this??

jim_thompson5910 · Answer

correct

anonymous · Answer

okay do i simplfy inside the root first?

jim_thompson5910 · Answer

yes

anonymous · Answer

(-5.4,0.4)

jim_thompson5910 · Answer

very good, you got the two solutions

anonymous · Answer

thank you for your help and the formula

jim_thompson5910 · Answer

you're welcome