Question

Hello... This might be a stupid question, but I don't seem to understand to pick an arbitrary number... I have the following problem;
x+y=3
y-x=3...
Now I know that for the first problem it becomes y=x+3, now from here, do u just pick any number or how do select the number to =x?

Answer 1

you want to pick and arbitrary number?

Answer 2

is that your question?

Answer 3

Yes . I think that's what it's called? What I'm trying to figure out is how to pick a number for x?

Answer 4

its just a non specific number
its not a trick

Answer 5

Ok??? How is it that you come up with this number? At first I thought, I'd just do the slope, but that was not the correct way to figure this out...

Answer 6

So basically you just pic any number to do this exercise?

Answer 7

Are you asking how to solve a system of equations? That's what your example looks like.

Answer 8

yes. I want to know how to pick the number for x? to solve for y...

Answer 9

You don't pick a number for x. To solve for y means to isolate y on one side of the equation.

Answer 10

right?

Answer 11

I think you mean substitution. Using the substitution method, you will solve one equation for y and substitute the other side of that equation into the second equation in place of the y. That will give you an equation with only one variable.

Answer 12

Starting with your first equation:
\(x+y=3 \implies y=3-x\)
So you will put \(3-x\) into the other equation in place of y.

Answer 13

There may be a problem with your question. It doesn't seem to have a solution....