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OpenStudy (anonymous):
Yes..
OpenStudy (anonymous):
Determine the geometric partial sum . (2 points)
Part 2: In complete sentences, explain the necessary steps required to find the partial sum. Include an explanation of whether this partial sum is divergent or convergent in nature. (3 points)
OpenStudy (anonymous):
lemme get the problem
OpenStudy (anonymous):
\[\sum_{i=1}^{7}3(2)^{i-1}\]
OpenStudy (anonymous):
is dis too complicated for your feeble minds? >:D
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OpenStudy (anonymous):
Take 3 outside \[\sum_{}^{}\]
OpenStudy (anonymous):
Now find \[a_{1}\] by substituting 1 in i.
OpenStudy (anonymous):
Then find \[a_{2}\]
OpenStudy (anonymous):
Divide a2 by a1 to find r
OpenStudy (anonymous):
i dont get it :/
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OpenStudy (anonymous):
Okay! I'll do it for you.
OpenStudy (anonymous):
You are a lifesaver!
OpenStudy (anonymous):
We have \[\sum_{i=1}^{7}3(2)^{i-1}\]
OpenStudy (anonymous):
Take 3 outside.
OpenStudy (anonymous):
so multiply ? what u mean take 3 outside?
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OpenStudy (anonymous):
\[3\sum_{i=1}^{7}(2)^{1-1}\]
OpenStudy (anonymous):
Oh :P
OpenStudy (anonymous):
So we have our first term after putting i=1.
OpenStudy (anonymous):
Let it be a1. Our a1=3
OpenStudy (anonymous):
Then plug i=2. We get 6. Let it be a2.
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OpenStudy (anonymous):
Now to find r, divide a2 by a1.
OpenStudy (anonymous):
We get r=2
OpenStudy (anonymous):
Getting it?
OpenStudy (anonymous):
YESH.
OpenStudy (anonymous):
Now we have a1=3, r=2 and our k=7
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OpenStudy (anonymous):
Use sum formula
OpenStudy (anonymous):
Your answer will be 381
OpenStudy (anonymous):
THANK YOU.
OpenStudy (anonymous):
OpenStudy (anonymous):
You're welcome again Gab
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