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Mathematics 15 Online
OpenStudy (anonymous):

HEEEELLLP. @mathsabc

OpenStudy (anonymous):

Yes..

OpenStudy (anonymous):

Determine the geometric partial sum . (2 points) Part 2: In complete sentences, explain the necessary steps required to find the partial sum. Include an explanation of whether this partial sum is divergent or convergent in nature. (3 points)

OpenStudy (anonymous):

lemme get the problem

OpenStudy (anonymous):

\[\sum_{i=1}^{7}3(2)^{i-1}\]

OpenStudy (anonymous):

is dis too complicated for your feeble minds? >:D

OpenStudy (anonymous):

Take 3 outside \[\sum_{}^{}\]

OpenStudy (anonymous):

Now find \[a_{1}\] by substituting 1 in i.

OpenStudy (anonymous):

Then find \[a_{2}\]

OpenStudy (anonymous):

Divide a2 by a1 to find r

OpenStudy (anonymous):

i dont get it :/

OpenStudy (anonymous):

Okay! I'll do it for you.

OpenStudy (anonymous):

You are a lifesaver!

OpenStudy (anonymous):

We have \[\sum_{i=1}^{7}3(2)^{i-1}\]

OpenStudy (anonymous):

Take 3 outside.

OpenStudy (anonymous):

so multiply ? what u mean take 3 outside?

OpenStudy (anonymous):

\[3\sum_{i=1}^{7}(2)^{1-1}\]

OpenStudy (anonymous):

Oh :P

OpenStudy (anonymous):

So we have our first term after putting i=1.

OpenStudy (anonymous):

Let it be a1. Our a1=3

OpenStudy (anonymous):

Then plug i=2. We get 6. Let it be a2.

OpenStudy (anonymous):

Now to find r, divide a2 by a1.

OpenStudy (anonymous):

We get r=2

OpenStudy (anonymous):

Getting it?

OpenStudy (anonymous):

YESH.

OpenStudy (anonymous):

Now we have a1=3, r=2 and our k=7

OpenStudy (anonymous):

Use sum formula

OpenStudy (anonymous):

Your answer will be 381

OpenStudy (anonymous):

THANK YOU.

OpenStudy (anonymous):

OpenStudy (anonymous):

You're welcome again Gab

OpenStudy (anonymous):

:D

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

Can I go to sleep now Gab?

OpenStudy (anonymous):

I'm already 25 mins late

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