Question

Factor completely: 2ax + 4bx − 3ay − 6by

Prime

(a − 2b)(2x + 3y)

(a + 2b)(2x − 3y)

(a − 3y)(2x + b)

Answer 1

try grouping
2ax + 4bx − 3ay − 6by
= 2ax - 3ay + 4bx - 6by
can u continue ?

Answer 2

lol no

Answer 3

hint: take out a from the first 2 terms

Answer 4

idk

Answer 5

2ax - 3ay = a(2x - 3y)

a was common to both terms

Answer 6

So C?

Answer 7

now lets look at the last 2 terms to see if we can get 2x - 3y in parentheses
4bx - 6by
= 2b(2x - 3y)

so we have

a(2x - 3y) + 2b(2x - 3y)
2x - 3y is common

so the answer is

(a + 2b)(2x - 3y)

Answer 8

so b

Answer 9

sorry C

Answer 10

notice i grouped the 2ax and - 3ay together because each of the last 3 options add a in the first parentheses

Answer 11

hope this has helped