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Factor completely: 2ax + 4bx − 3ay − 6by Prime (a − 2b)(2x + 3y) (a + 2b)(2x − 3y) (a − 3y)(2x + b)
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try grouping 2ax + 4bx − 3ay − 6by = 2ax - 3ay + 4bx - 6by can u continue ?
lol no
hint: take out a from the first 2 terms
idk
2ax - 3ay = a(2x - 3y) a was common to both terms
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So C?
now lets look at the last 2 terms to see if we can get 2x - 3y in parentheses 4bx - 6by = 2b(2x - 3y) so we have a(2x - 3y) + 2b(2x - 3y) 2x - 3y is common so the answer is (a + 2b)(2x - 3y)
so b
sorry C
notice i grouped the 2ax and - 3ay together because each of the last 3 options add a in the first parentheses
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hope this has helped
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