In a soccer tournament, teams receive 6 points for a winning game, 3 points for a trying game, and 1 point for each goal they score. what algebraic expression models the total number of points that a soccer team receives in a tournament?????? suppose one team wins two games and ties 1 game, scoring a total of 5 goals. how many points does the team receive????

Question

anonymous · Answer

let:
x = games won
y = games played
z = goal
p = points

p = 6x + 3y + z

-----
team won 2 games, ties 1 and scores total of 5 goals in all 3 games played. total point?

p = 6(2) + 3(1) +(5) = 20 points

anonymous · Answer

wouldn't it be =5 instead of +5?? just wondering

anonymous · Answer

for my answer I got 12w+3T+5g=(20points)         is that correct????

anonymous · Answer

what would be 5 or +5 ?
do you mean the term for goals ?
the total points are sum of each individual points for; games won; tried and goals

i am confused by the term "tried" in the question, does a tied game and lost game both count as "tried" game ?

anonymous · Answer

it doesn't say tried in the question maybe I had a typo...  3 points for a tying game

anonymous · Answer

your answer is correct, that is total is 20 points, but the expression is not.

see the coefficients in your equation:
12w+3T+5g=20 points

when you substitute values in variables, variables have to be omitted.

the equation has to be:

total points -->  p = 6W + 3T + G
substituting the wins, ties and goals in the above expression.

p = 6(2) + 3(1) + 5 = 20  <-- see variables, W, T and G were substituted with values given in the question