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square root of x minus 7 end root plus 5 equals 11
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You want to isolate the square root portion of your problem, which can be done by subtracting 5 from both sides, leaving us with: \[\sqrt{x-7}= 6\] Now we want to raise both sides to the 2nd power. This allows us to eliminate the square root we have. \[(\sqrt{x-7})^{2}= 6^{2}\] After the root is gone you just isolate x. Think you can go from there?
Yes, thank you :)
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