Question

can someone help me answer letter a? the magnitude and direction of its velocity at t = 2? plssss. .i need help!

"A batter hits a baseball so that it leaves the bat w/ an initial speed of 37 m/s at an initial angle of 53.1degrees.(a) Find the position of the ball, magnitude and direction of its velocity, when t=2sec.(b) Find the time when the ball reaches the highest point of its flight, and find its height at his point."

Answer 1

The question is a basic physics question, so it ignores air friction (not all do). This means that you get to assume a symmetrical trajectory, and that gravity acts only on the vertical component of the motion, and not the horizontal component.

So:

Start by resolving your initial velocity into X and Y components, based on the initial angle.

Gravity acts only on the vertical Y component, so apply 2 seconds of acceleration (deceleration) from gravity, and find out the new Y component at t=2.

Your X component hasn't changed, so you've now got your t=2 X and Y components for the velocity. Add them back together for your final t=2 velocity. Convert back to an angle (if they want that), and take the magnitude of the summed vector for the speed.

That get you moving?

Answer 2

thank you :)