Question

12u^6-16u^5/2u^2

How do I do that

Answer 1

\[\large \frac{u^{m}}{u^{n}} = u^{m-n}\]

Answer 2

But there's two numbers on top

Answer 3

And if you subtract them it's 4u/2u^2 and if you do that it can't divide can it?

Answer 4

??? what how do you get 4u ?

you cant subtract they are not like terms

Answer 5

Oh. Well, how do you subtract the two powers if there's 3 powers in the question o:

Answer 6

basic understanding of fractions it would seem...
\[\frac{x+y}{2} = \frac{x}{2} + \frac{y}{2}\]

Answer 7

But there's still 3 powers. If there's 3 powers, how do I subtract them?

Answer 8

\[\frac{12u^6-16u^5}{2u^2}=\frac{4u^5(3u-4)}{2u^2} \]
\[= 2u^{5-2}(3u-4) =2u^{3}(3u-4)\]

Answer 9

Ohhhh. So then do I just distribute?

Answer 10

Or is it done?