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Mathematics 9 Online
OpenStudy (anonymous):

How do I factor this? x^2-11xy-12y^2

OpenStudy (anonymous):

?

OpenStudy (anonymous):

Quadratic formula?

OpenStudy (anonymous):

Not sure. Isn't it trinomial

OpenStudy (anonymous):

Nevermind

OpenStudy (anonymous):

What's getting me is there's two letters rather than one

OpenStudy (anonymous):

Ignore the y first, then factor it like normal and add a y at the back of the term with no x's after factoring

OpenStudy (anonymous):

Example x^2 - 2xy + y^2 Ignore the y's. x^2 - 2x + 1 Factor it (x - 1)^2 Add the y to the term with no x's. (x - y)^2

OpenStudy (anonymous):

But y's to the second power to

OpenStudy (anonymous):

Yes, it is and my method will work for that

OpenStudy (anonymous):

so (x+12)(x-1)??

OpenStudy (anonymous):

No

OpenStudy (anonymous):

It's (x - 12)(x + 1) , somehow you got the signs mixed up

OpenStudy (anonymous):

Now add the y's to the constant number in each binomials

OpenStudy (anonymous):

Umm... so (x-12y)(x+y)?

OpenStudy (anonymous):

Yes

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