Which of the following describes how to graph the line whose equation is y =2/3 x - 1? Plot the point (0, -1), move up 3 and right 2, plot the point, and draw the line through these 2 points. Plot the point (0, -1), move up 2 and right 3, plot the point, and draw the line through these 2 points. Plot the point (-1, 0), move up 2 and right 3, plot the point, and draw the line through these 2 points.
@ash2326 @AkashdeepDeb @amistre64 help
@dumbcow
the answer is option B. Do you have any query to be cleared?
yeh just how you got tht i ....can you explain
Yeah sure thing.. Look the question actually says to plot the point (0,-1) because if you put zero in x's place then the line equation would look like y = 2/3 * 0 -1 So y would become -1 itdelf. That is why they tell us to first plot (0,-1) And then they tell us to move 2 up and three right because if you move 2 up y value bcome -1. +2 which is 1 And then they tell us to kove three right so that x value becomes 3 So they actually are tellinus to plot the point (3,1) Which fits the equation again because y=2*3/3 aq which is 2-1 which is the y value 1 when x is 3!! Get it? :D
That aq at the end is -1! :D
XP thanks ill be shure to put this in my notes
Please excuse my grammer! I am on my iPad right now.
haha np
Haha..You're welcome!
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