Which factor can you cancel from the numerator and denominator to simplify 7 times x minus 21 all over 18 minus 6 times x.?
\[\Large \frac{7x-21}{18-6x}\]Factoring a 7 out of each term in the top,\[\Large \frac{7(x-3)}{18-6x}\]Factoring a 6 out of each term in the denominator,\[\Large \frac{7(x-3)}{6(3-x)}\]This next step is a little tricky, lemme know if it confuses you. We want to factor out a -1 from each term in the denominator,\[\Large \frac{7(x-3)}{-6(x-3)}\] See our cancellation from here? Hah, you're a duck! :D
so > 7 from the numerator and 6 from the denominator ?
and yes yes i am :D
We had to do some factoring to find our `matching` factor in the numerator and denominator. The `matching` factors are the ones that will cancel out.
ohh i see
OHHHHHH thanks mate haha XD
np c:
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