(2x+3) / 4 - (3x-5) / 3 = 2 solve for x.
First thing I would do is get rid of those denominators. You can get rid of something in the denominator my multiplying everything by that same number. So for example, if I wanted to get rid of that 4 in your first denominator, I would simply multiply everything by 4: \[\frac{ 4(2x+3) }{ 4 }-\frac{ 4(3x-5) }{ 3 }=(2)(4)\]Note how I multiplied every term by 4. You must make sure everything gets multipliedif you do this. Now those 4's on that left fraction will cancel out and I will have this: \[(2x+3)-\frac{ 4(3x-5) }{ 3 }=8\] Also note how I keep thoseparenthesis. It's a very good habit to have, it'll help make sure you do not get the wrong signs or forget to do some sort of operation. Now I have that 3 left in the 2nd denominator. I can eliminate that in the same method I did with the 4, by multiplyong every by 3 like so: \[3(2x+3) - \frac{ (3)(4)(3x-5) }{ 3 }=(8)(3)\]Again, I was careful to multiply everything by 3. Also notice how I just leave a bunch of things grouped together, but not actually multiplied out. This is also sometimes a good strategy. It lets you visualize what you're doing better in case you miss something or need to backtrack. Now, I can cancel out that 3 in the second denominator, which will leave me with this. \[3(2x+3)-4(3x-5)=24\] That was probably the trickiest part of this problem. I'll leave it to you to see if you can finish the rest from here : )
but we have to do it this way for the test: can you show me where i am going wrong?\[\frac{ 2x+3 }{ 4} - \frac{ 3x-5 }{ 3 } = 2\]
then do this: \[\frac{ 3(2x+4) }{ 12 } - \frac{ 4(3x-5) }{ 12 } = 2\]
then: \[\frac{ 6x+12 - 12x - 2x +20 }{ 12 }\]
where am i going wrong??
@daftkillz - where did u get the "-2x" term in this equation ??
sorry delete that
typo
pretend its not there
its still wrong -_-
also it should be 3(2x+3)
your error is in distributing 3(2x + 3) you have 6x + 12..... which isn't correct
so it should be: 6x+9 - 12x +20 = 2
because thats still wrong..
RHS should be 12*2=24 right ?
wait what?
well if you change the 2 to 24... multiply every term by 12 you can solve your equation
wow made a stupid as mistake ok i get it now
i forgot 2 multiply the rhs by 12
thanks
Amy is twice as old as lucy. Three years from now the sum of their ages will be 42. how old is amy?
how do you do this?
can u share the equations u wrote for this problem ?
i did this: Let lucy= L and amy= A 3L + 3 = 42 3L = 39 2L = 26 therefore amy = 26 but the answer is 24
???
do it one by one... also you forgot to add three years to lucy's or amy's age :P
thts all
ohhh ok thanks :D
Join our real-time social learning platform and learn together with your friends!