Question

What is the equation of the line described below written in slope-intercept form?

the line passing through point (4, -1) and perpendicular to the line whose equation is 2x - y - 7 = 0


y = -1/2x + 1
y = 1/2x - 1
y = 2x + 1

Answer 1

C

Answer 2

Nope

Answer 3

could you explain ho to work it out??

Answer 4

how*

Answer 5

What is the gradient perpendicular to 2x - y - 7 = 0 ?

Answer 6

i have no idea ma"am i havent learned that termonology yet

Answer 7

1x-2y-7=0??

Answer 8

You can find the gradient from 2x - y - 7 = 0,

2x - y - 7 = 0

y = 2x - 7

From
y = mx + b

m is the gradient, 2
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Then to find the perpendicular gradient, use
\[m_1m_2=-1 \\ 2m_2=-1 \\ m_2=-\frac{1}{2}\]
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Now you have a gradient and coordinate (4,-1)
You can now use the point slope form to finish it up
\[y-y_1=m(x-x_1) \\ y+1=-\frac{1}{2}(x-4)\]\[...\]