MEDALS WILL BE REWARDED!! HELP!! Find all solutions to the equation. 7 sin2x - 14 sin x + 2 = -5
That is sin(2x) or sin^2(x)?
sin2x so yes sin(2x)
@Psymon help?
You sure its not sin squared? O.o
hahaha its is sin squared
sorry @Psymon
Okay, that makes wayyyy more sense then o.o Okay then yeah, treat this like a quadratic. Instead of x^2, x, number, we have sin^2, sin, number. So what I can do is set everything equal to 0 and factor out a 7. Doing this leaves us with: \[7(\sin ^{2}x-2sinx+1)=0\]So this is basically the same as if it were: \[7(x ^{2}-2x+1)=0\] Would you know how to factor that?
x=0,1,2?
Well this factors to 7(x-1)(x-1) = 0. Do you see how?
yes i do.... so my
zeros would be 1 and 0?
Just 1. But since we're dealing with sinx and not actually x, we have 7(sinx-1)(sinx-1) = 0 Meaning we have to solve sinx = 1.
and how do we do that?
Well, it requires knowledge of the unit circle. With values like 0 and 1, though, they are a little bit easier to find even if you don't know theunit circle that well. So cosine refers to x values and sin refers to y values, and a unit circle is a circle with a radius of 1. |dw:1376878785286:dw| So given that sin is a y coordinate, where on that circle is the y-coordinate equal to 1?
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