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Mathematics 20 Online
OpenStudy (anonymous):

MEDALS WILL BE REWARDED!! HELP!! Find all solutions to the equation. 7 sin2x - 14 sin x + 2 = -5

OpenStudy (psymon):

That is sin(2x) or sin^2(x)?

OpenStudy (anonymous):

sin2x so yes sin(2x)

OpenStudy (anonymous):

@Psymon help?

OpenStudy (psymon):

You sure its not sin squared? O.o

OpenStudy (anonymous):

hahaha its is sin squared

OpenStudy (anonymous):

sorry @Psymon

OpenStudy (psymon):

Okay, that makes wayyyy more sense then o.o Okay then yeah, treat this like a quadratic. Instead of x^2, x, number, we have sin^2, sin, number. So what I can do is set everything equal to 0 and factor out a 7. Doing this leaves us with: \[7(\sin ^{2}x-2sinx+1)=0\]So this is basically the same as if it were: \[7(x ^{2}-2x+1)=0\] Would you know how to factor that?

OpenStudy (anonymous):

x=0,1,2?

OpenStudy (psymon):

Well this factors to 7(x-1)(x-1) = 0. Do you see how?

OpenStudy (anonymous):

yes i do.... so my

OpenStudy (anonymous):

zeros would be 1 and 0?

OpenStudy (psymon):

Just 1. But since we're dealing with sinx and not actually x, we have 7(sinx-1)(sinx-1) = 0 Meaning we have to solve sinx = 1.

OpenStudy (anonymous):

and how do we do that?

OpenStudy (psymon):

Well, it requires knowledge of the unit circle. With values like 0 and 1, though, they are a little bit easier to find even if you don't know theunit circle that well. So cosine refers to x values and sin refers to y values, and a unit circle is a circle with a radius of 1. |dw:1376878785286:dw| So given that sin is a y coordinate, where on that circle is the y-coordinate equal to 1?

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