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Mathematics 15 Online
OpenStudy (anonymous):

2x+5=13

OpenStudy (eyust707):

welcome =)

OpenStudy (mary.rojas):

question? x?

OpenStudy (eyust707):

Solve for x. (I'm assuming)

OpenStudy (mary.rojas):

get x by itself. subtract the 5 and then divide by two on both sides an get.................

OpenStudy (psymon):

OS is dead, so everyone is gathering to the new question, lol.

OpenStudy (eyust707):

once school starts it will be over loaded

OpenStudy (psymon):

Can't wait.

OpenStudy (kainui):

So we can start by seeing that this is a system of equations of 1 variable so we can represent this as a vector in a matrix equation after subracting 5 from both sides (since both sides are equal, anything you do to either side must be equal.) \[\left[ 2 \right]\left[ x \right]=\left[ 8 \right]\] now we can see that it's easily solved by row reduction. \[\left[ 2| 8 \right]\] now we can divide the whole row by 2 to get it into reduced row echelon form, which is basically where you have the identity matrix on the left. \[\left[ 1| 4 \right]\] There you go, x=4.

OpenStudy (eyust707):

ouch that might be a bit advanced for @marlic

OpenStudy (psymon):

Haha, wtf @Kainui

OpenStudy (eyust707):

although a great way of thunkning about it

OpenStudy (kainui):

This is what i think about every time I see an algebra question posted in the "Linear Algebra" section. Although technically this question was safe... Well they weren't. Mwahahaha.

OpenStudy (mary.rojas):

lol yeah I will be one overloading the q box ><

OpenStudy (eyust707):

=D

OpenStudy (psymon):

I have to wait til the spring for my matrix and linear algebra courses :/

OpenStudy (eyust707):

...and going back to 8th grade here is how we solve for x:

OpenStudy (eyust707):

|dw:1376898487548:dw|

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