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\[\frac{( 4h - 1) }{ 1+h } ; h=2\]
Put 2 in place of h
4(2) -1
then 1+2
Is it as simple as that? I think I'm over thinking the problem making it harder than it is
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then what ever you get from the first answer put it over the second answer
\[\frac{ 4(2)-1 }{ 1+2 }\]
\[\frac{ 8-1 }{ 3}\]
7/3?
|dw:1376919612923:dw|
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