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without dividing show that 8 is the factor of 256
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use them as 2^k numbers
show that 8 = 2^k, and 256 = 2^(kn)
err, 2^(k+n) :)
8=2^3 and 256=2^8 now???
8 = 3+?
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\[a^{k+n}=a^k~a^n\]
since 8 = 2^3; 256 = 2^(3+5) =2^3 2^5 = 8 2^5
ok get it...thanks
youre welcome
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