Question

Establish this identity:
ln|sec(θ) + tan(θ)| + ln|sec(θ) - tan(θ)| = 0

Answer 1

ln(secθ+tanθ)(secθ-tanθ) [lnA+lnB = lnAB]
ln(sec^2θ - tan^2 θ) = ln(1) [sec^2θ - tan^2 θ = 1]
ln(1) = 0!
LHS = RHS!!
Proved!! :D

Answer 2

O.O Why you so amazing, so fast! Thank you for clearing it up for me! You're so magical~

Answer 3

MagicalLYFARTING? ;)
That is the one of the wierdest usernames I have heard in a while! :D
Glad you understood it btw! :D

Answer 4

Thank you I take that as a compliment :D
And thank you once more so so helping. ^w^