Question

The legs of a right triangle measure 5√2 cm and 4√2 cm. Find the area.

Answer 1

do you have choices ?

Answer 2

10√2 sq. cm
20 sq. cm
20√2 sq. cm

Answer 3

In a right triangle, the right angle is formed by the legs.
That means, for every right triangle, , one leg is the base and the other leg is the height.
The area of a triangle is the product of the base and height divided by 2, so just multiply the lengths of the legs and divide by 2 to find the area.

Answer 4

A = 1/2 . b. h

Answer 5

what is 5\(\sqrt{2}\) x 4\(\sqrt{2}\)

Answer 6

ok so 5√2 x 4√2 = area

so 20 square root 4

Answer 7

ok, that is right, so what is square root of 4

Answer 8

2

Answer 9

ok so you have 20 x 2 = ?

Answer 10

that is the base x height
Area = 1/2 base x height, so what is half of it

Answer 11

it's 20 square root 2 isn't it?

Answer 12

\(A = \dfrac{bh}{2} \)

\(A = \dfrac{5\sqrt{2} \times 4\sqrt{2}}{2} \)

Ok so far?

Answer 13

10 square root 2

Answer 14

No.
Just follow what I am doing from the response just above.

We just plugged in the lengths of the legs in the formula. I did it above. Are you ok with that?

Answer 15

yes

Answer 16

what is 20 x 2 equal to ????

Answer 17

40

Answer 18

\(A = \dfrac{20 \times \sqrt{2 \times 2}}{2}\)

\(A = \dfrac{20 \times \sqrt{4}}{2}\)

\(A = \dfrac{20 \times 2}{2}\)

\(A = \dfrac{20 \times 2}{2}\)

\(A = \dfrac{40 }{2}\)

\(A = 20\)

Answer: the area is \(20 ~cm^2\).

Answer 19

ok then

Answer 20

the area is 1/2 of 40

Answer 21

Keep this in mind:

\(\sqrt{a} \times \sqrt{b} = \sqrt{ab} \)

The way you use that rule is like this:

What is \(\sqrt{2} \times \sqrt{8} = ~? \)

\(\sqrt{2} \times \sqrt{8} = \sqrt{2 \times 8} = \sqrt{16} = 4 \)

Answer 22

ok