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Mathematics 21 Online
OpenStudy (anonymous):

4x+3y=-5 x=y-3

OpenStudy (akashdeepdeb):

Put the x value in the first equation! And then solve! :D

OpenStudy (anonymous):

,Where did you get the X value?

OpenStudy (anonymous):

Do I solve 4x+3y=-5?

OpenStudy (anonymous):

So to solve for that I would subsitute 3 for 0 4x=-5 -5/4=-1.25?

OpenStudy (akashdeepdeb):

In the second equation :) The x value is ALREADY given to you in TERMS of y! So put it in the first equation as 4(y-3) + 3y = -5! Expand the brackets and find the y value here! :D

OpenStudy (anonymous):

So that gives me 4y-12+3y=-5

OpenStudy (anonymous):

errr 4x-12+3y=-5

OpenStudy (akashdeepdeb):

So 7y = 7 And y = 1 right? :D

OpenStudy (anonymous):

Wait how did you get the 7?

OpenStudy (akashdeepdeb):

Add 12 to both sides! :D

OpenStudy (anonymous):

ok so adding 12 to both sides gives me 4x+3y=7

OpenStudy (anonymous):

adding 4 &3 gives me 7y 7y=7 y=1

OpenStudy (akashdeepdeb):

JoStudy Best Response Medals 0 So that gives me 4y-12+3y=-5 YOU WROTE THIS RIGHT!! :D

OpenStudy (akashdeepdeb):

YES!! :D

OpenStudy (anonymous):

Gotcha! Thanks!

OpenStudy (akashdeepdeb):

Okay so now! AFTER GETTING THE y VALUE Put it in the second equation [MORE CONVENIENT TAN FIRST] And get the x value! :D

OpenStudy (anonymous):

So I use y=1 in one of the original equations x=1-3 1-3 x=-2

OpenStudy (anonymous):

Thank you!

OpenStudy (akashdeepdeb):

:) Good job! :)

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