Question

HELP ME ANSWER THESE 5 8TH GRADE QUESTIONS ILL GIVE YOU A SHOUTOUT GOOD REPORT AND A MEDAL

Answer 1

@amistre64 @Algebra2013 @androidonyourface @abb0t @Ashleyisakitty @aeerw @BulletWithButterflyWings @BrandonGarza777 @Bearsfan98 @brittany12345678910 @brianjr227 @bashirk @campbell_st @countonme123 @ChrisJP @ChrisLove @chaylacryder @cambrige @Clonest @dan815 @dmezzullo @dirtydan667 @DontLikeMathButOhWell @Dreweed @DebbieG

Answer 2

WHOEVER SOLVES THE MOST GETS FEEDBACK SHOUTOUT AND MEDALS

Answer 3

hmmm, someone needs to click on the caps-lock key :P

Answer 4

honey, I am sorry to say that feedback shoutouts are not allowed.

Answer 5

let's do the 1st one only

Answer 6

I ment medal and a testimonial

Answer 7

the shaded area is where the inequality is true
the non-shaded ares is where the inequality is false

so you have the graph, let's pick a POINT NOT IN THE LINE

say (0, 0) that's not in the line

let's test the 1st choice

Answer 8

Take any point in the shaded region!!
Substitute them in the equation Trial n Error!!

Answer 9

*equation(S)

Answer 10

Get the equation to which the graph belongs!!........Thats it!! Nice and Easy!!

Answer 11

(0,0)

-6(0)+(0) < 3
0 < 3
now is 0 really less than 3? yes, is true, but notice we picked a point on the non-shaded area, the false area

the solution choice will give us false on the non-shaded, and true on the shaded

so it's not the 1st choice

Answer 12

(0, 0) for the 2nd choice # remember, we need it to be FALSE there, is non-shaded

6(0)+(0) < 3
0 < 3

well, low and behold, 0 is less than 3, it's true, thus is not our guy

Answer 13

(0, 0) for the 3rd choice # remember, we need it to be FALSE there, is non-shaded

6(0)-(0) < -3
0 < -3

is 0 really less than -3? well, not -3 is smaller than 0, thus is false, thus is our choice

Answer 14

so I used the "false" area of the graph

but you could have done just the same using the "true" area of the graph, the shaded area
the only difference is that the POINT in the SHADED AREA has to yield TRUE for the inequality

Answer 15

why did I pick this time the false area? well just to make it simple using (0, 0)

Answer 16

im lost