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Mathematics 8 Online
OpenStudy (anonymous):

Find the total area (in terms of K) of the prism. Place "K" last in your formula. T.A. =

OpenStudy (anonymous):

OpenStudy (anonymous):

would you be able to help me with this one?

OpenStudy (anonymous):

@surjithayer

OpenStudy (jdoe0001):

hmm,, P = 20" meaning the Perimeter of the pentagonal face alone is 20 k = apothem

OpenStudy (jdoe0001):

so if all 5 equal sides of the regular pentagonal face are 20 total, that is the perimeter how much is 1 side only?

OpenStudy (anonymous):

4

OpenStudy (jdoe0001):

so, notice the figure, you have for lateral sides, 5 rectangles, 4x6 each

OpenStudy (anonymous):

24 is the lateral surface but I am not sure how to calculate the "2B" part of the formula

OpenStudy (jdoe0001):

and then you add to that sum of those 5 rectangles area, the area of the pentagon above and below, area of a regular polygon = \(\bf \cfrac{1}{2} (apothem)(perimeter)\)

OpenStudy (anonymous):

120 would actually be the lateral area

OpenStudy (jdoe0001):

yes, to get the total area add the pentagonal faces

OpenStudy (jdoe0001):

\(\bf\cfrac{1}{2} (apothem)(perimeter) \implies \cfrac{1}{2} (k)(20) \implies \cfrac{20k}{2} \implies 10k\)

OpenStudy (anonymous):

side=20/5=4 area of the rectangles=5*(20*6)=600 total area= 600+10k+10k=600+20k

OpenStudy (anonymous):

thank you!

OpenStudy (anonymous):

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