Find the total area (in terms of K) of the prism. Place "K" last in your formula. T.A. =
would you be able to help me with this one?
@surjithayer
hmm,, P = 20" meaning the Perimeter of the pentagonal face alone is 20 k = apothem
so if all 5 equal sides of the regular pentagonal face are 20 total, that is the perimeter how much is 1 side only?
4
so, notice the figure, you have for lateral sides, 5 rectangles, 4x6 each
24 is the lateral surface but I am not sure how to calculate the "2B" part of the formula
and then you add to that sum of those 5 rectangles area, the area of the pentagon above and below, area of a regular polygon = \(\bf \cfrac{1}{2} (apothem)(perimeter)\)
120 would actually be the lateral area
yes, to get the total area add the pentagonal faces
\(\bf\cfrac{1}{2} (apothem)(perimeter) \implies \cfrac{1}{2} (k)(20) \implies \cfrac{20k}{2} \implies 10k\)
side=20/5=4 area of the rectangles=5*(20*6)=600 total area= 600+10k+10k=600+20k
thank you!
|dw:1376945811215:dw|
Join our real-time social learning platform and learn together with your friends!