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Mathematics
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ln^(x^2)=((ln^x)^2) * (1/(ln^3))
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wait, let me draw it!
\( \Huge ln^{x^2}=(ln^x)^2 \times \cfrac{1}{ln^3}\ \ \ ?\)
Yes! that's the equation! sorry it was so confusing!
.... aren't yo missing a base value there?
isn't the natural log a value by its self?
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natural log or e = 2.71 i think
the left side ln(?)^(x^2)
right, I meant, the values are missing, lemme rewrite it some
\(\huge ln\square^{x^2}=(ln\square^x)^2 \times \cfrac{1}{ln\square^3}\)
|dw:1376950320820:dw|
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