factor x^2-11x+24
two numbers that multiplied together to yield 24, and added together to yield -11.
I need to factor, not solve
get x from quad. formula then put it in this form (x-first x value) (x- second x value)
or you think of two numbers that multiplied together to yield 24, and added together to yield -11.
(3 + -1x)(8 + -1x) Sorry that should be it lol. I thought it was to solve.
these two numbers are -8 and -3. notice hwen they are added, it is -11, when they are multiplied, it is +24. then you simply dissect the middle term with x to look like x^2-8x-3x+24. then factor the first two terms, and last two terms together
Factor box this problem\[x^2 -11x +24\] How to Factor box: Create a window with a corner like this:|dw:1376965482070:dw| Then put the terms around the box:|dw:1376965523784:dw| Split the terms into their factors, hence "factor box"|dw:1376965594243:dw| Since 3+8= 11, use these terms.:|dw:1376965742252:dw| Then put them into their factors:|dw:1376965836893:dw| Then you get this:\[(x+3)(x+8)\] Multiply them back and you will get your original equation. So, your factors are (x+3) and (x+8) NOTE: This ONLY WORKS IF you can find factors to equal the middle term. For example: \[x^2 + 10x +5\] wont work because 5*1 does not equal 10.
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